World · India Bureau
Australian woman discovers pregnancy 24 hours before premature birth
An Australian mother received a shocking diagnosis when she learned she was pregnant just one day before delivering an extremely premature infant. Her daughter, born at 21 weeks and three days gestation, has since become Australia's most premature surviving baby.
LSN India ·
The unnamed Australian woman had no inkling she was expecting until medical professionals confirmed her pregnancy—a revelation that came with an urgent caveat: she could give birth within 24 hours. The diagnosis proved prophetic when her daughter, Makerita Tanuvasa, arrived shortly thereafter at just 21 weeks and three days of gestation, an extraordinarily early stage of fetal development.
The newborn weighed a mere 351 grams at birth, requiring immediate intensive medical intervention to survive. Despite her critical condition, Makerita defied medical expectations and went on to become Australia's most premature surviving infant, a distinction that underscores the advances in neonatal care and the resilience of even the tiniest patients.
After spending more than four months in intensive care units, where she received specialized treatment and round-the-clock monitoring, Makerita eventually stabilized enough to return home with her family. Her survival represents a remarkable medical achievement, offering hope to other families facing similarly challenging circumstances with extremely premature births.